1 + Cos 2a<u>- Cos 4a -Cos 6a</u> = 2Cos² a - 2Cos 5a Cos a =
=2Cos a( Cos a - Cos5 a)=<u>2 Cos a·2Sin 3a Sin 2a </u>.
Sin 3a - Sin aCos 2a = Sin 3a -1/2(Sin 3a - Sin a) = 1/2Sin 3a + 1/2 Sin a =
=1/2·2Sin 2aCos a =<u>Sin 2a Cos a </u>
При делении = 4Sin 3a
А=5 в=-21 с=4
D=441-80=361
х=21-19/10=0.2
х=21+19/10=4
16a²-b²=(4a)²-b²=(4a+b)(4a-b)