-3-×> 4×+7
-×-4×> 7+3
-5×> 10
-×> 10÷5
-×> 2
×<2
2ˣ+2⁻ˣ=17/4 2ˣ=z>0
z+1/z=17/4 z²-17/4z+1=0
4z²-17z+4=0 D=17²-4*4*4=289-64=225 √D=15
z1=1/8[17-15]=1/4=2⁻² z2=1/8[17+15]=4=2²
2ˣ¹=2⁻² x1=-2 2ˣ²=2² x2=2
1/4 (cos(2 x)+cos(4 x)+cos(6 x)+1) = 1
Ответ:
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\