1)сокращаем:
2x(2x-y)=0
2)переносим y:
2x=y
3)находим x:
х=y/2
4*(2^2x) - 5*(2^x) + 1 = 0
2^x = z
4z² - 5z + 1 = 0
D = 25 - 4*4*1 = 9
z₁ = (5 - 3)/8
z₁ = 1/4
z₂ = (5 + 3)/8
z₂ = 1
2^x = 1/4
2^x = 2^(-2)
x₁ = - 2
2^x = 1
2^x = 2^0
x₂ = 0
Х^2+2x-24=0
D=b^2-4ac=4+96=100
x1=(-2+10):2=4
х2=(-2-10):2=-6