D H2=M(CxHy) / M(H2)
M(CxHy)= M(H2)* D H2=2*21=42
w(C)/M (C) : w(H)/M(H)=85,7/12:14,3/1=7.141:14.3=1:2 (CH2)n M(CxHy)/M(CH2)=42/14=3
(CH2)3=C3H6
С2H2 + [O]+ H2O = CH2(OH)-CH2(OH)
CH2(OH)-CH2(OH) + 2KBr = CH2Br-CH2Br + 2KOH
CH2Br2-CH2Br = C2H2 + 2HBr
C2H2 + Ag2O = CH3COH + 2Ag
<span>2H</span>⁺<span>N</span>⁺³<span>O</span>₂⁻²<span>+2K</span>⁺<span>J</span>⁻<span>+H</span>₂⁺<span>S</span>⁺⁶<span>O</span>₄⁻²<span> = J</span>₂°<span> + 2N</span>⁺²<span>O</span>⁻²<span> + K</span>₂⁺<span>S</span>⁺⁶<span>O</span>₄⁻²<span> + 2H</span>₂⁺<span>O</span>⁻²
N⁺³+1e=N⁺² 2 ок-ль, вос-ние
2J⁻-2e=J2° 1 в-ль, ок-ние
1. Al +3 О -2
2. Zn +2 NO3 -1
3. Mg +2 Cl -1
4. Ca +2 O -2
5. H +1 F -1
6. S +6 O -2
7. K +1 OH -1
8. K +1 Mn +7 O -2
9. H +1 S +6 O -2
<span>дано:<span>
m(NaCl</span>) = 585 г<span>
найти: n(NaCl</span>), <span>
решение:
M(NaCl</span>) = 23 +35,5 = 58,5г\моль<span>
n(Cl</span>₂) = m\M = 585 г\58,5 г\моль = 10 моль<span>
ответ:n(NaCl</span>) = 10 моль<span><span> </span></span></span>