дано
m(ppa H2SO4) = 200 g
W(H2SO4) = 20%
η(Na2SO4) = 80%
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m прак (Na2SO4)-?
m(H2SO4) = 200 * 20% / 100% = 40 g
M(H2SO4) = 98 g/mol
n(H2SO4) = m/M = 98 / 40 = 2.45 mol
H2SO4+Na2O-->Na2SO4+H2O
n(H2SO4) = n(Na2SO4) = 2.45 mol
M(Na2SO4) = 142 g/mol
m теор (Na2SO4) = n*M = 2.45 * 142 = 347.9 g
m практ (Na2SO4) = 347.9 * 80% / 100% = 278.32 g
ответ 278.32 г
ответ во вложении))))))))))))))))))))))))))))))))))))
CaO+3C=CaC2 +CO, CaC2+2h2o=Ca(OH)2+C2H2,C2H2+2h2=C2H4,C2h4=hcl=c2h5cl,c2h5cl +Naoh=c2h5oh+NaCl, c2h5oh+cacl2=cacl2 +co2+3h2o☺
2H2+O2=2H2O
V=n*Vm
n(H2)=2моль
n(H2):n(H2o)=2:2
n(H2O)=2моль
V(H2O)=2*22,4=44,8 л