Решите пожалуйста: 4(1-0,5x)=-2(3+2x) 5(x+1,2)=12,5x 0,4(6x-7)=0,5(3x+7) 7(1,4x+1,8)-27,6=10,1x 0,3(5x-7)-3(0,2x+3,2) 4(1,2x+3,7
korolek 91
<span>4(1-0,5x)=-2(3+2x)
4-2х=-6-4х
-2х+4х= - 6-4
2х= - 10
х= - 10/2
х= - 5
</span><span>5(x+1,2)=12,5x
5х+6=12,5х
5х-12,5х= - 6
-7,5х= - 6
7,5х=6
х=6/7,5
х=0,8
</span><span>0,4(6x-7)=0,5(3x+7)
2,4х-2,8=1,5х+3,5
2,4х-1,5х=3,5+2,8
0,9х=6,3
х=6,3/0,9
х=7
</span><span>7(1,4x+1,8)-27,6=10,1x
9,8х+12,6-27,6=10,1х
9,8х-10,1х=27,6-12,6
-0,3х=15
х=15/(-0,3)
х=50
</span>0,3(5x-7)-3(0,2x+3,2)=1,5х-2,1-0,6х-9,6=0,9х-11,7<span>
</span><span>4(1,2x+3,7)-2,8-5,2x=4,8х+14,8-2,8-5,2х=12-0,4х
</span><span>1,2(3x+5)=2(2,4x-3,6)
3,6х+6=4,8х-7,2
3,6х-4,8х= - 7,2-6
-1,2х=-13,2
</span>1,2х=13,2
х=13,2/1,2
х=11
1)∫(2x-1)^2dx
u=2x-1
du=2dx
1/2∫u^2du=u^3/6+C
((x-1)^3)/6+c
2)∫10sin5xdx=10∫sin5xdx=-2cos5x+C
3)∫(2x-1/x^2)dx=∫2xdx-∫x^(-2)dx=x^2+x^(-1)+C=x^2+1/x+C
3/4х=-8
3х=4/(-8)
х=-32/3
х=-10 2/3
3/4*(-10 2/3)=-8
-3/4*32/3=-8
-8=-8