10 - 3b при b = -4
10 - 3 * (-4) = 10 + 12 = 22
Log₅ (1/35)+ log₆ 36- log₇ 1- log₄ 4=
Log₅ (35⁻¹)+ log₆ 36- log₇1- log₄ 4 =-
Log₅ 35 +1-0-1=-
Log₅(5·6)=-(
Log₅5+ Log₅7)=-1-
Log₅7
5x-12=t
2t²-10t+12=0
D=100-4*2*12=4
t1=10+2/4=3
t2=10-2/4=8/4=2
5x-12=3
x1=3
5x-12=2
x2=14/5=2,8
У=1/2х
х=у:1/2
х=у*2
х=15*2
х=30
Ответ: 30.