10cos²x+17sin x-16 = 0
10*(1-sin²x)+17sin x-16 = 0
10-10sin²x+17sin x-16 = 0
-10sin²x+17sin x-6 = 0
10sin²x-17sin x+6 = 0
sin x = t, sin²x = t², t∈[-1; 1]
10t²-17t+6 = 0
D = 289-4*10*6 = 289-240 = 49
t1 = (17-7)/20 = 1/2
t2 = (17+7)/20 = 1 1/2 - не подходит.
sin x = 1/2
x = (-1)^n*π/6+πn, n∈Z
Ответ:
3дм75см 2м33дм 8а54м 1га65а
Пошаговое объяснение:
1) 4 + (-10) = 6
4 - 10 = -6
-(10-4)=-6
-6=-6
2) -7.5 + 3.5 = -4
-(7.5-3.5)=-4
-4=-4
3) -12.1+5.1=-7
-7=-7
4)7.8 + (-2.8)=5
7.8-2.8=5
5=5
5) -3.4+(-4.6)=-8
-3.4-4.6=-8
-(3.4+4.6)=-8
-8=-8
6) -1.25+(-1.75)=-3
-3=-3
<N=x
<M=2x
<K=6x
x+2x+6x=180
9x=180
x=180:9
x=20-<N
20*2=40-<M
20*6=120-<K