8-4z>6-6z
-4z+6z>6-8
2z>-2
z>-1
Ответ:z>-1
<span>6(4x-5)^2 = 6*(16x^2 - 40x+25) =96x^2 -240x+150
</span>
4x-6>=0
x>=3/2
5-x>=0
x<=5
область определения 1-2х=0 отсюда x не равно 1/2
3/2<х<5
(1)-(-2,5)⁻²+(-2/5)⁻²=0
(2) -4⁻³+(-4/5)⁻²=-1/4³+(-5/4)²=-1/4³+(5/4)²=
=(-4+5)/4³=1/64
= (cos(720 + 60) - ctg ( 540 -45)) * sin (360 - 135) =
= (cos 60 - ctg(-45)) * sin (-135) = (cos 60 + ctg 45) * (- sin 135) =(1/2 +1) * (- sgrt2/2)=
= 3/2 * ( -sgrt2/2)= - 3 sgrt2 / 4