6^x≤6^1
(6 > 1) x ≤ 1
x-1 < 0
x < 0
3^x≤3^1
(3 > 1) x ≤1
(1/3)^x ≥3
3^(-x) ≥ 3
(3 > 1) -x ≥3
x ≤ - 3
3^x ≥ 3^1
(3 > 1) x ≥ 1
(2+x)³ = x³ + 6x² + 12x + 8
(a-2)³ = a³ - 6a² +12a - 8
(5-b)³ = -b³ +15b² -75b+125
(y+3)³ = y³ +9y²+27y+27
A6=a1+d(n-1
a6=-4+1,4*5=-4+7=3
Ответ: 3.