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Log₁/₂(x)<1
ОДЗ: x>0
log₁/₂(x)<log₁/₂(1/2)
0<1/2<1
x>1/2 (входит в ОДЗ)
Ответ: (1/2;+∞)
√25-√49= 5 - 7 = -2
√16 * √9 = 4 *3 =12
3√4 - √36 = √(3² · 4) - √36 =√36 -√36 = 6 - 6 =0
√64 : √ 900 = 8 : 30 = 8/30 = 4/15
B₁> b₃ на 6
b₂ < b₄ на 3
решаем:
b₁ - b₁q² = 6 ⇒ b₁(1 - q²) = 6
b₁q³ - b₁q = 3, ⇒ -b₁q(1 - q²) = 3 разделим 2-е ур-е на 1-е
получим: q = -1/2
b₁(1 - q²) = 6,⇒ b₁*(1 -1/4) =6,⇒ b₁ *3/4 = 6,⇒ b₁ = 8.
Ответ: 8; - 4; 2: -1