Первообразная F(x) = ∫f(x)·dx + C
1) f(x) = (1 + 2x)³
F(x) = ∫ ((1 + 2x)³/2) d(1 + 2x) + C = ((1 + 2x)⁴/2)/4 + C = (1 + 2x)⁴/8 + C
2) f(x) = (3x +1x)³
F(x) = ∫((1 + 2x)³/3) d(3x + 1) + C = ((3x + 1)⁴/3)/4 + C = (3x +1)⁴/12 + C
42-6×7/37-11=42-42/26=0/26=0
2x²-2x-15=0
D=4+120=124=√124
x1,2 = 2+-√124/4
4y = 4y
( 3x + 1 )*2 = ( x + 3 )*2
6x + 2 = 2x + 6
4x = 4
x = 1
4y = 2x + 6
4y = 2 + 6
4y = 8
y = 2
ОТВЕТ ( 1 ; 2 )