((2b-5a)(2b+5a))/(10ab +1/2b+5a)=(2b-5a)/10ab
-0,1x(2x^2+6)(5-4x^2)=(-0,2x^3-0,6x)(5-4x^2)=-1x^3+0 ,8x^5-3x+2,4 x^3=1,4x^3 +0,8x^5-3x
Решение смотри на фотографии
1) x1*x2 = -24/1 = -24
x1+x2 = +2/1 = 2
x1 = -4, x2 = 6
2) x1*x2 = -2*(-7) = 14 = c
x1+x2 = -2-7 = -9 = b
a<span>х²+bx+c=0
пусть а =1
</span><span>х²-9x+14=0
3) </span>x1*x2 = -6/1 = -6
<span>x1+x2 = -5/1 = -5
x1 = 1, x2 = -6
4) </span>x1*x2 = 4*(-5) = -20 = c
x1+x2 = 4-5 = -1 = -b, b =1
a<span>х²+bx+c=0
пусть а =1
</span><span>х²+x-20=0 </span>