Ответ 3!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
4сosx/sinx:(1+cos²x/sin²x)+2sin²2x+1=0
4cosx/sinx*sin²x/(si²x+cos²x)+2sin²2x+1
4cosx*sinx+2sin²2x+1=0
4sinxcosx+4sin²xcos²x+1=0
(2sinxcosx+1)²=0
(sin2x+1)²=0
sin2x=-1
2x=-π/2+2πk
x=-π/4+πk/2,k∈z
Platit: 2 na 0 =1, tak kak 5 na 0 = 1, 10 na 0 = 1, poka a ne rovno 0 i a na 0 =1.
V našom priklade budet:
5-x = 2 na 0
5-x = 1, x = 5-1, x =4