Tg(2x+π/6)≥-√3
-π/3+πn ≤ 2x+π/6 < π/2+πn, n∈Z
-π/3-π/6+πn ≤ 2x < π/2-π/6+πn, n∈Z
-π/2+πn ≤ 2x < π/3+πn, n∈Z
-π/4+πn/2 ≤ x < π/6 +πn, n∈Z
x∈[-π/4+πn/2 ; <span>π/6 +πn), n∈Z</span>
Ну очень легкое уравнение))
А1=7*1-2=5
а2=7*2-2=12
а3=7*3-2=19
а4=7*4-2=26
а10=7*10-2=68
А. а²-10а+25 - 2а²+6а = - а²-4а+25
в. (2х)² - (3у)² = 4х² - 9у²