5х-10+11-3х-9=0
2х-8=0
2х=8
х=4
Y^-2y+1-y^2-6y+y-7=0
4y+8=0
4y=0-8
у= -8:4
у= -4
Lim┬(x→0)〖(1+x-x^2)/(〖2x〗^2+5x+4)〗 =
=lim┬(x→0)〖(1+x-x^2):x^2/(〖2x〗^2+5x+4):x^2〗=
=lim┬(x→0)〖(1/x^2+x/x^2-x^2/x^2)/(4x^2/x^2+5x/x^2+4/x^2)〗=
= lim┬(x→0))〖(1/x^2+1/x-1)/(4+5/x+4/x^2)〗=-1/4
14. х = 3х
х = 0
Ответ: 0
15. х^2 - 3х + 2 = 0
D = 9 - 8 = 1
x1 = 3 - 1 / 2 = 1
x2 = 3 + 1 / 2 = 2
b / m + 1
b = 2
m = 1
2 / 1 + 1 = 3
Ответ: 3
16. 8х^4 + х^3 + 64х + 8 = 0
Пусть х^3 = у, тогда (8xy+y) + (64x+8) = 0
y(8x+1) + 8(8x+1) = 0
(y+8)(8x+1) = 0
y+8 = 0
y = -8
8x+1 = 0
8x = -1
x = -1/8
x^3 = -8, корней нет
Ответ: -1/8