1. 4a(3a2b)*bs^2=24a^2*b^2*s^2=6(2abs)^2
второй степени
2.a) (4ac^2)^3*a^3c/2=64a^3c^6a^3*c/2=32a^6c^7
б) (5x^2*y^3*z^4)^3/(3*x^2*y*z^2)^2=125/9(x^2*y^7*z^8)
3.
(3*x^3)^2+5x^4-(5x^4-4x)-9x^6-3=5
9*x^6+5x^4-5x^4+4x-9x^6-3-5=0
4x-8=0
x=2
Sin(7π/2-3x)=sin(2π+(3π/2-3x))=sin(3π/2-3x)=-cos3x
(√10-2√2)/(2√5-4)=√2(√5-2)/2(√5-2)=√2/2
-cos3x=√2/2
cos3x=-√2/2
3x=-3π/4+2πn U 3x=3π/4+2πn
x=-π/4+2πn/3 U x=π/4+2πn/3
Ответ наим полож корень х=π/4
Y = - x - 1
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