<span> x<3 3-x+7-x=10-2x
√(З-х)^2 + √(7-х)^2 </span> 3<x<7 x-3+7-x=4
x>7 x-3+x-7=2x-10
0.7y - 0.2x + 0.3y +0.2x = 1y = -0.14
4(x+1)-6(2-x)>2,
4x + 4 - 12 + 6x > 2,
10x - 8 > 2,
10x > 2 + 8,
10x > 10,
x > 10:10,
x > 1.
Ответ: x>1.
(1+t²)²=(1)²+2*1*t²+(t²)²=1+2t²+t⁴