1+sinx·cosx-3cos²x=0
sin^2x+cos^2x+sinxcosx-3cos^2x=0/cos^2x
tg^x+1+tgx-3=0
a^2+a-2=0
D=3
a1=-2
a2=-1 x=-pi/4+pin
3) sinxcosx-cos^2x=1
tgx-1=1
tgx=2
x=arctg2+pin
<span>14; 19; 29; 40; 45 число (45) </span>
(8(m-n)+3(3m-n)/(6(m-n)^2
=(m-n)(8+3))/6(m-n)^2=
11/(6(m-n)
Cos2p/4=cosp/2=0; sin15p/4=-sinp/4=
ответ: