X-π/3=π/4+πn
x=π/4+π/3+<span>πn
x=7</span>π/12+<span>πn</span><span>. n∈Z</span>
A+140=b (1)
0,6b-64=0,7a (2)
(1) во (2)
0,6(a+140)-64=0,7a
0,6a+84-64=0,7a
0,6a+20=0,7a
0,6a-0,7a=-20
-0,1a=-20
-a=200
a=-200
a+140=b
-200+140=b
b=-60
Ответ: a=-200, b=-60
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