1)(8a³-b³)/(4a²-b²)=(2a-b)(4a²+2ab+b²)/(2a+b)(2a-b)=(4a²+2ab+b²)/(2a+b)
2)(ab+ac)/(ab-3b+ac-3c)=a(b+c)/(b(a-3)+c(a-3))=
=a(b+c)/(a-3)(b+c)=a/(a-3)
-5x + 9(-1 + 2x) = 9x - 1
-5x - 9 + 18x = 9x - 1
-5x + 18x - 9x = -1 + 9
4x = 8
x = 2.
-2sin(3x+π/6)*sinπ/6=-2sin(x+π/6)*sinπ/6
sin(3x+π/6)=sin(x+π/6)
sin(3x+π/6)-sin(x+π/6)=0
2sinxcos(2x+π/6)=0
sinx=0⇒x=πn,n∈z
cos(2x+π/6)=0⇒2x+π/6=π/2+πk⇒2x=π/3+πk⇒x=π/6+πk/2,k∈z
3a+7b-6a-4b; -3а+3b)))))))))))])