3×6×3:2×√3
3×3×3√3
Ответ:27√3.
(√12-5)(√12+5)=√12²-5²=12-25=-13
1) log₂ 5=<u> 1 </u>
log₅ 2
2) <u> 1 </u> + 16log₅ 2 - 8 = <u>1 + 16log₅² 2 - 8log₅ 2</u>
log₅ 2 log₅ 2
3) <u> 1+16log₅² 2 - 8log₅ 2 </u> * log₅ 2 = 1+16log₅² 2 - 8log₅ 2 =
log₅ 2
= 16log₅² 2 - 8log₅ 2 + 1= (4log₅ 2 - 1)²
4) √(4log₅ 2 -1)² = |4log₅ 2 - 1| = 4log₅ 2 - 1 = log₅ 2⁴ - 1
5) 4log₅ 12.5 = 4log₅ (25/2) = 4(log₅ 25 - log₅ 2) =
= 4(2 - log₅ 2) = 8 - 4log₅ 2 = 8 - log₅ 2⁴
6) log₅ 2⁴ - 1 + 8 - log₅ 2⁴ = 7
Ответ: 7
2/3 + 7/15 - 2а/12 = 2*20 / 60 + 7*4 / 60 - 2а*5 / 60 =
= 40+28-10а / 60 = 68-10а / 60 = 2(34-5а) / 2*30 = 34-5а / 30
|x+5|=2-2x1)x≥-5x+5=2-2x3x=-3x=-12)x<-5-x-5=2-2xx=7Ответ: -1