<span>(2x+3)(x−1)=12</span>
<span>2х²-2х+3х-3=12</span>
<span>2х²-2х+3х-3-12=0</span>
<span>2х²+х-15=0</span>
<span>D=1+120=121=11²</span>
<span>х= (-1±11)/4</span>
<span>х1= (-1+11)/4= 10/4 = 5/2 = 2,5</span>
<span>х2= (-1-11)/4= -12/4 = -3</span>
<span>Ответ: -3 ; 2,5. </span>
<span>(два корня)</span>
<em><span>=)...€∫∫</span></em>