1)sin22,5=√(1-cos45)/2=
√(1-√2/2/2)=√(2-√2)/4=1/2*√(2-√2)
sin²75=(1-cos150)/2=(1-cos(180-30))/2=
(1+sin30)/2=(1+1/2)*1/2=3/4
OTBET 1/2*(2-√2)-3/4=1-√2/2-3/4=
1/4-√2/2
2)2cos²4x-1=0
cos8x=0
8x=π/2+πk
x=π/16+πk/8
Cos²x-sin²x+sin²x+√3cosx=0
cosx(cosx+√3)=0
cosx=0
x=π/2+πn,n∈z
cosx=-√3<-1 нет решения
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1) 36400:100*95\%=34580 человек
Ответ: 34580