Sinx^2+cosx^2=1
<span>cosx=√(1-9*11/100)=+√(0.01)=+0.1 т. к. cosx>0 при 0<x<90</span>
1
(1/2a-1/3b²)³=1/8a³-1/4a²b²+1/6ab^4-1/27b^6
2
(1/6x²+1/2y³)³=1/216x^6+1/24x^4y³+1/8x²y^6+1/8y^9
3
(10a³+1/3b³)³=1000a^9+100a^6b³+10/3a³b^6+1/27b^9
4
(0,3a^5+0,5a)³=0,243a^15+0,135a^11+0,225a^7+0,125a³
5
(0,1x^4-1/2x³)³=0,001x^12-0,015x^11+0,075x^10-0,125x^9
6
(1,5m³+0,3m^4)=3,375m^9+2,025m^10+0,415m^11+0,027m^12
9б^+12б+4+49-9б^-12б=49+4
2cos^2(x) + 3x - 3 = 0
2(1+cos2x)/2 + 3x-3 = 0
1+cos2x + 3x - 3 = 0
(cos2x) + (3x-2) = 0
1) cos2x = 0
2x = π/2 + πn
x = π/4 + πn/2
2) 3x-2 = 0
x = 2/3
общих корней не вижу..возможно их и нет! не знаю!