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Решение в вложении, снова.
= (а^1/2+в^1/3)^6 = а^(1/2*6)+в^(1/3*6) = а^3+в^2
19a -7b+12
<u>5a-8b+2</u> =3
8a-5b+2
5a-8b+2=3(8a-5b+2)
5a-8b+2=24a-15b+6
5a-24a-8b+15b+2-6=0
-19a+7b-4=0
19a-7b+4=0
19a-7b+12=19a-7b+4+8=0+8=8
Ответ: 8
3(2a-5b)^2-12(a-b)^2=<span>3((2a-5b)^2-(2(a-b))^2)=3(2a-5b-2a+2b)(2a-5b+2a-2b)=-9a(4a-7b)=-9*1\4(1\4*4-7*(-1\3))=-7.5
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