А) Fe + 2HCl = FeCl2 + H2↑
FeCl2 + 2NaOH = Fe(OH)2↓ + 2NaCl
Fe(OH)2 + 2HCl = FeCl2 + 2H2O
б) 2Na + 2NaOH = 2Na2O + H2
Na2O + H2O = 2NaOH
в) 2Ca + O2 = 2CaO
CaO + H2O = Ca(OH)2
г) ZnO + 2HCl = ZnCl2 + H2O
2NaOH + ZnCl2 = Zn(OH)2↓ + 2NaCl
<span>4)MgO
MgO + 2HCl = MgCl2 + H2O
MgO + NaOH = </span>≠
N2 + 3H2 = 2NH3
1) n(NH3) = m(NH3)/M(NH3) = 17г/17г/моль = 1 моль;
V(NH3) = n(NH3) × Vm = 1моль × 22,4л/моль = 22,4л;
2) Составляем пропорцию:
V1/V2 = K1/K2 => V(NH3)/V(N2) = 2/1;
22,4л/x = 2/1;
2x = 22,4;
x = 11,2.
Ответ: 11,2 л.