a) 3x-x = 0 => 2x = 0 => x = 0
б) 3x-3x = 4 => 0 = 4 => нет корней
в) x^2 + x - 6 = 0 => D = 1 + 24 = 25 => x = (-1 +- 5)/2 => x1 = 2, x2 = -3
г) x^2 + 4x +3 = 0 => D = 16 - 12 = 4 => x = (-4 +- 2)/2 => x1 = -1, x2 = -3
д) x^2 - 4x = 0 => x(x-4) = 0 => x1 = 0, x2 = 4
е) x^3 + 2 - 3x = 0 => (x-1)*(x^2 + x - 2) = 0 => x1 = 1, x^2 + x - 2 = 0 => x2 = x1 = 1, x3 = -2
= 14t^2 + 12t + 31,5t + 27 =
= 14t^2 + 43,5t + 27
1)(x+y)/(x-y)+x/y=(xy+y²+x²-xy)/y(x-y)=(x²+y²)/y(x-y)
2)(x+y)/(x-y)-y/x=(x²+xy-xy+y²)/x(x-y)=(x²+y²)/x(x-y)
3)(x²+y²)/y(x-y) *(x²+y²)/x(x-y)=(x²+y²)²/xy(x-y)²
4)(x²+y²)²/(x²-y²)² : (x²+y²)²/xy(x-y)²= (x²+y²)²/(x-y)² (x+y)² *xy(x-y)/(x²+y²)²=xy/(x+y)²
Вырази во 2-ом уравнение у через х
потом подставь в 1-ое уравнение вместо у,тогда найдешь х
дальше найдешь у