1/х=(2/у)+4а
(4/у)+8а-6/у=3+4а
-2/у=3-4а
у=-2/(3-4а);3-4а≠0;а≠3/4
1/х=(-4/(3-4а))+4а=(-4+12а-16а²)/(3-4а)
х=(3-4а)/(-4+12а-16а²)
-4+12а-16а²≠0
16а²-12а+4≠0
Д=144-256<0
-4+12а-16а²<0
ответ а≠3/4
(a±b)²=a²±2ab+b²
(m-3)²=m²-2*3m+3²=m²-6m+9
(x+5)²=x²+2*5x+5²=x²+10x+25
(6+y)²=36+12y+y²
(4+d)²=16+8d+d²
(p+q)²=p²+2pq+q²
(z²-y)²=z⁴ - 2z²y+y²
5-2x<=9 5-2x>=0
2x>=-4 2x<=5
x>=-2 x<=2,5
[-2;2,5]
x>2,5 2x-5<=9 2x<=14 x<=7
[2,5;7]
x[-2;7]
7-(7-(-2))/2=7-4,5=2,5
ответ 2,5
√3,6*√8,4/√0,21=√[(36*0,84)/0,21]=√(36*4)=6*2=12