Log2(5x-73)-2=log2(3)
ОДЗ: 5x-73>0; 5x>73; x>14,6
Решение:
log2(5x-73)= log2(3)+2
log2(5x-73)= log2(3)+ log2(4)
log2(5x-73)= log2(12)
5x-73=12
5x=12+73
5x=85
x=17
1) а2 - 2ba - 3b2 + a2 = 2a2 - 2ba - 3b2
3) 3b2 - 10 2 + 8b - 5b2 = -2b2 - 100 + 8b
5) 36c2 - 12c - 6c2 + 1 2 = 30c2 - 12c + 1
0,3x=8-2
0.3x=6
x=20
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Удачи!