1)X^2+3x=0
X(x+3)=0
X=0
X+3=o
X=-3
2)x^2-4x-5=0
D=(-4)^2-4*1*(-5)=36
x1,2 = (4+-√36) / 2 = (4+-6) / 2 = 2+-3
x1 = 2-3 = -1,
x2 = 2+3 = 5.
G ( 0 ) = V 0 = 0
g ( 1 ) = V ( 5 - 1 ) = 2
g ( 3 ) = V ( 15 - 9 ) = V 6
<span>(123+375)*24:(212-129)=</span>11,952/83=144
Пусть t=x`2
тогда
t`2-17t+16=0(p=-17,q=16)
t1+t2=-p
t1*t2=q
=
t1+t2=17
t1*t2=16
=>
t1=16
t2=1
3. Обратная замена:
x`2=16; x`2=1
x=+-4; x=+-1