1)Pb2+ + 2No3-
2)K+ + Cl-
3)Zn2+ + So42-
M(p-pa) = m(сахара)/W(p-pa) = 2/0,05 = 40 г
m(H2O) = m(p-pa) - m(сахара) = 40 - 2 = 38 г
1) <span>E</span>2<span>O</span>5<span> + H</span>2<span>O = 2HEO</span>3<span> (Е = N, Р, I)</span>
<span>2)<span>EO</span>2<span> + H</span>2<span>O = H</span>2<span>EO</span>3<span> (Е = С, Se)</span></span>
<span>3)не помню</span>
<span>4)<span>EO</span>3<span> + H</span>2<span>O = H</span>2<span>EO</span>4<span> (E = S, Se, Cr)</span></span>
2Сa+O2=2CaO
n(Ca)=8г:40г/моль= 0.2моль
n(O2)=0.1моль
V(O2)=0.1моль*22.4л/моль=2.24л