log(a) b + log(a) c = log(a) bc
a^n*a^m = a^(n+m)
ОДЗ y>0 x>0
log(2) y + log(2) 3 = log(2) x
log(2) 3y = log(2) x
x= 3y
3^x*3^y^2 = 3^4
x+y^2 = 4 подставляем из первого
y^2 + 3y - 4 = 0
D=9+16=25 y12=(-3+-5)/2 = -4 1
y1=-4 Нет по ОДЗ
y2=1
x=3y=3
ответ (3 1)
2) (4b - 1)(4b + 1) - (4b - 1)² = 16b² - 1 - (16b² - 8b + 1) = 16b² - 1 - 16b² + 8b - 1 = 8b - 2
При b = - 4: 8 * (- 4) - 2 = - 32 - 2 = - 34
3)
3x + 2 (4x - 7) = 8
3x + 8x - 14 = 8
11x = 8 + 14
11x = 22
x = 2
Ответ: 1
4. А1, Б3, В2
<span>2√x-9=0
</span>2√x=9
√x=4.5
x=4.5 * 4.5 = 20.25