1)(m-9)^2
2)4a-0,49= (2корень a-0,7)(2корень a+0,7)
3)(с+4)(с^2-4с*16)
4)2(р^2-n^2)=2(p-n)(p+n)
- 2 ≤ 2 - 3x ≤ 5
- 2 - 2 ≤ - 3x ≤ 5 - 2
- 4 ≤ - 3x ≤ 3
- 1 ≤ x ≤ 4/3
1 < (x + 4)/3 < 7 /*3
3 < x + 4 < 21 / - 4
- 1 < x < 17
F(x) = sin²x + cos²x
f(x) = 1
f'(x) = 0.
Ответ: f'(x) = 0.
<span>12cos<span>²</span> (2-3x) + 4 sin (2-3x) -11 = 0</span>
<span>12(1-sin<span>²(2-3x))+4sin(2-3x) -11=0</span></span>
<span><span>12-12sin<span>²(2-3x)+4sin(2-3x)-11=0</span></span></span>
<span><span><span>-12sin<span>²(2-3x)+4sin(2-3x)-11+12=0</span></span></span></span>
<span><span><span><span>12sin<span>²(2-3x)-4sin(2-3x)-1=0</span></span></span></span></span>
<span><span><span><span><span>Пусть sin(2-3x)=t, -1<t<1</span></span></span></span></span>
<span><span><span><span><span>12t<span>²-4t-1=0</span></span></span></span></span></span>
<span><span><span><span><span><span>D=16+4*12=64</span></span></span></span></span></span>
<span><span><span><span><span><span>t=4+8/24=1/2</span></span></span></span></span></span>
<span><span><span><span><span><span>t=4-8/24=-1/6</span></span></span></span></span></span>
<span><span><span><span><span><span>И делаем обратную замену</span></span></span></span></span></span>
<span><span><span><span><span><span>sin(2-3x)=1/2 sin(2-3x)=-1/6</span></span></span></span></span></span>
<span><span><span><span><span><span>Далее получаем корни..</span></span></span></span></span></span>