<span>1
tgx>1/</span>√3
<span>x</span>∈(π/6+πk;π/2+πk,k∈z)<span>
2
tg2x</span>≥1/√3
π/6+πk≤2x≤π/2+πk,k∈z
<span>x</span>∈[π/12+πk/2;π/4+∈z)<span>
3
tgx/3<1/</span>√3
<span>-</span>π/2+πk<x/3<π/6+πk,k∈z
<span>-3</span>π/2+3πk<x<π/2+3πk,k∈z<span>
4
tg(x-</span>π/9)≤-1/√3
-π/2+πk≤x-π/9≤-π/6+πk,k∈z
-π/2+π/9+πk≤x≤-π/6+π/9+πk,k∈z
-7π/18+πk≤x≤-π/18+πk,k∈z