по т Виета х1+х2=-р х1*х2= q
x^2-(a+b)x+ab=0
Lg(lg(lgx)) = 0 <=> lg(lgx) = 1 <=> lgx = 10 <=> x = 10^10.
(2,5*√0,64+1/8)/√256=(2,5*0,8+0,125)/16=2,125/16=0,1328125
Ex + 2e2x+ex
y' = 1- √(e2x+ex+1) = 2+ex+√(e2x+ex+1)-ex√(e2x+ex+1)-2e2x-ex =
2+ex+2√(e2x+ex+1) 2+ex+2√(e2x+ex+1)
= (2-ex)√(e2x+ex+1)+2+ex-2ex
2+ex+2√(e2x+ex+1)