<span>4x^2-4xy+y^2+5y-10x=<span>(y-2x)*(y-2x+5)</span></span>
(6 2/3)*6=40
40*0,2=8
8-3 5/9=4 4/9
4 4/9 : 2=2 2/9
2 10/45 +8 3/45=10 13/45
Ответ: 10 13/45