Ответ:
Объяснение:
(c³)³×c³:c¹¹= c⁹×c³:c¹¹=c¹²:c¹¹=c¹=c
А)-7 12/23-5,93-71 13/27-(-7 12/23)-6,07=-7 12/23-5,93-71 13/27+7
12/23)-6,07=(-7 12/23+7 12/23)+(-5,93-6,07)-71 13/27=0-12-71 13/27=-83
13/27
б)-25-24-23-...-1+0+1+...+32+33=(-25+25)+(-24+24)+...+(-1+1)+0+
+26+27+28+29+30+31+32=236
ОДЗ 9-х²≥0
х=3,ч=-3
_ + _
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-3 3
х∈х[-3;3]
9-x²=0⇒x²=9⇒x=-3 U x=3
cosx=√3/2⇒x=+-π/6+2πn⇒x=-π/6, x=π/6