CH3COOH+C2H5OH---CH3COOC2H5+H2O
N(CH3COOH)=3.6/(12*2+4+16*2)=0.06 моль
N(CH3COOC2H5)=N(CH3COOH)=0.06 моль
m(CH3COOC2H5)=0.06*(12*4+16*2+8)=5.28 г
W=4.5/5.28*100%=85,2%
Ответ 85,2 %
А) Mr(MgO) = 24+16= 40
б) ω(Mg)= Ar(Mg)/Mr(MgO) = 0,6*100% = 60%
ω(O) = Ar(O)/Mr(MgO) = 0,4*100% = 40%
Cu(OH)2, Fe(OH)3, KOH, Ni(OH)2, LiOH, Ba(OH)2