<span>sin^2 a * tg a - cos^2 a=</span>
<span>= sin^3 a / cos a - 1+ sin^2 a =</span>
<span>= sin^3 a / sqrt(1-sin^2 a) - 1+ sin^2 a =</span>
<span>= 1/27 / sqrt(1-1/9) -1 + 1/9 = </span>
<span>= 1/(9sqrt(8) -8/9 = </span>
<span>= (sqrt(2)-32)/36</span>
Решениеееееееееееееееееее
Х+7=16
х=16-7=9
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B³-3bc+3b³+8bc-4b³=5bc
6x²y-xy²-8x²y+2xy²=xy²-2x²y=xy(y-2x)