<span>MgO+<span>H2O=Mg(OH)2</span></span>
<span><span><span>MgO+2<span>HNO3=Mg(NO3)2+H2O</span></span></span></span>
<span><span><span>Al2O3+6<span>HNO3=2Al(NO3)3+3H2O</span></span></span></span>
<span><span><em>Al2O3</em><span> + 3H2O = 2Al(OH)3 </span></span></span>
<span><span><span><span>Al2O3 + 2KOH + 3H2O = 2K[Al(OH)4]</span></span></span></span>
<span><span><span><span><span>Fe(OH)2+H2O=Fe(OH)3</span></span></span></span></span>
<span><span><span><span><span><em>Fe(OH)3 + 3KOH = K3[Fe(OH)6] </em></span></span></span></span></span>
<span><span><span><span><span><em><span> Fe(OH)2+2HNO3=<em>Fe(<em>NO3)2+2H2O</em></em></span></em></span></span></span></span></span>
<span><span><span><span><span><em><span><em><em><span>2KOH+<span>H2S =K2S+2H2O</span></span></em></em></span></em></span></span></span></span></span>
1.
Дано:
м(Al) = 34 г
Найти:
V(H2) = ?
m(Al2(SO4)3) = ?
Составим уравнение реакции :
34 г------------------------х г---------y л
2Al + 3H2SO4 = Al2(SO4)3 + 3H2^
27------------------------342----------2
Решение:
m(Al2(SO4)3) = (34 г * 342) : (2 * 27) = 215,33 г
m(H2) = (34 г * 3 * 2) : (2 * 27) = 3,78 г
m = p * v => m : p = v
p(H2) = 0.09 г/л (н. у.)
v(H2) = 3.78 г : 0.09 г/л = 42 л
Ответ: V(H2) = 42 л; m(Al2(SO4)3) = 215.33 г
2.
Дано:
м(BaCO3) = 122 г
м(СО2) = Х г
Составим уравнение реакции:
--_----------------x г-------122 г
2BaCO3 + 2 CO2 = 2BaCO3\/ + 2H2O
----171----------44-----------197
Решение:
Х = (2 * 44 * 122) : (2 * 197) = 27.25 г СО2
Ответ : 27.25 г СО2
1. Mg(NO3)2+ H2SO4= 2HNO3+ MgSO4
2. 2KCl+ Ba(OH)2= BaCl2+ 2KOH
NaOH=Na(+)+OH(-)
HNO3=H(+)+NO3(-)
MgCl2=Mg(2+)+2Cl(-)
K2CO3=2K(+)+CO3(2-)
Fe(NO3)3=Fe(3+)+3NO3(-)