<span>Опрелелите координату точки M отрезка AB , если A(-7) и B(5) и AM:AB=1:5
-A-------------M-----------------------------------------B
-7 x 5
I AM I=x-(-7)=x+7
</span>I AB I=5-(-7)=12
AM:AB=1:5
(x+7):12=1:5 ⇔5(x+7)=12 ⇔ x=(12-35)/5=-23/5= -4,6<span>
проверка
</span>I AM I=-4,6-(-7)=2,4 I AB I= 5-(-7)=12
AM:AB=2,4 :12=1:5
<span>( m-32,6).2,4=1,8</span>
<span>2,4m - 78.24 = 1.8</span>
<span>2.4m = 1.8 -+ 78.24</span>
<span>2.4m = 80.04</span>
<span>m= 80.04 : 2.4</span>
<span>m= 33.35</span>
3 = 1 + 1 + 1 = 1 + 0 + 2 = 1 + 2 + 0 = 2 + 0 + 1 = 2 + 1 + 0 = 3 + 0 + 0
102
111
120
201
210
300
1044 - сумма
10•10•8= 800, 205:80=160 (45) Все равно: 960 (45)