<em>(√(ху)-х)/(√(ху)-х)=</em><em>1</em>
<em>(25х-у)/(5√(ху)+у)=((5√х-√у)(5√х+√у))/(√у(5√х+√у))=(5√х-√у)/(√у)=</em>
<em>=(√у(5√х-√у))/у=</em><em>(5√(ху)-у)/у</em>
<em>можно и так (25х-у)/(5√(ху)+у)=(25х-у)(5√(ху)-у)/((5√(ху)+у)(5√(ху)-у))=</em>
<em>(25х-у)(5√(ху)-у)/(25ху-у²)=(25х-у)(5√(ху)-у)/((25х-у)*у)=</em><em>(5√(ху)-у)/у</em>
2^x * 5^x=100 По свойству степени А^x * B^x= (A*B)^x
Тогда (2*5)^x=100
10^x=100
10^x=10^2 <span>⇒ x=2
</span>Ответ: 2
(3+4)²+5²=74
3³+(6-2)³<span>=91</span>