3Br2 + 2Al = 2AlBr3 Сумма коэффициентов 7
5H2S + 2KMNO4 + 3H2SO4= 5S + K2SO4+2MnSO4+ 8H2O
C3H6 + Br2 = C3H6Br2
V(C3H6) = 22.4 l
n(C3H6) = V / Vm = 22.4 / 22.4 = 1 mol
n(Br2) = n (C3H6) = 1 mol
M(Br2) = 80 * 2 = 160 g/mol
m(Br2) = M * n = 160 * 1 = 160 g
150 мг - 2\%
x - 100\%
х = 150/0.02 = 7500 мг
Сl- СH2 - СH2 - СH(CH3) - СH3