Х=73-8
Х=65
Б)а=94-31
А=62
В)
A) y=(sin3x-cos3x)^2
y'=2(sin3x-cos3x)*(3cos3x+3sin3x)=6[(sin3x)^2-(<span>cos3x)^2]
b) y=(x^2)</span>√(4-7x^2)
y'=2x√(4-7x^2)+(x^2)*(1/2)*[<span>(4-7x^2)^(-1/2)]*(-14x)=
7x^3
</span>2x<span>√(4-7x^2) - ---------------
</span> <span>√(4-7x^2)</span>