Решение
3^(2x + 1) - 10*3^(x) + 3 = 0
3*3^(2x) - 10*3^(x) + 3 = 0
3^x = t
3t² - 10t + 3 = 0
D = 100 - 4*3*3 = 64
t₁ = (10 - 8)/6
t₁ = 1/3
t₂ = (10 + 8)/6
t₂ = 3
3^x = 1/3
3^x = 3⁻¹
x₁ = - 1
3^x = 3
x₂ = 1
P(0,1<X<0,6) = F(0,6) - F(0,1) = (0,6^2) - (0,1^2) = 0,36 - 0,01 = 0,35.
20*0,35 = 2*3,5 = 7.
Ответ. 7.
34
*13
-----
102
+ 340
-=------
442