C(HCl)=14,6/36,5=0,4 моль
V(HCl)=0,4*22,4=8,96 л
1)CH4+2O2 --> CO2+2H2O
2)2C2H6+702 --> 4CO2+6H2O
3)<span>2ZnS+3O2 --> 2ZnO + 2S02
</span>4)<span>2Al2S3 + 9O2 --> 2Al2O3 + 6SO2
5)</span> 2C6H6 + 15O2 --> 12CO2 + 6H2O
6)C6H12O6 + 6O2 --> 6CO2 + 6H2O
7)C12H22O11 + 12O2 -->12CO2 + 11H2O
Ответ:
Объяснение:
Mr(CO) = 12+16=28
W(C) = Ar(C) *n / Mr(CO) *100% = 12*1 / 28 *100% =43%
W(O) = Ar(O) *n / Mr(CO) *100% = 16*1 / 28 *100% = 57%
1. C2H5OH (t>140°,h2so4(k))= C2H4 + H2O
C2H4 + Br2 = C2H4Br2
C2H4Br2 + 2KOH (сп)= C2H2 + 2KBr + 2H2O
3C2H2 (Cakt,t=420°)= C6H6
2. m(CuS)= 181 г
H2SO4, O2
V(SO2) — ?
CuS + H2SO4 = CuSO4 + H2S
181/96 = x/34
x = 64 г
2H2S + 3O2 = 2H2O + 2SO2
64/68 = y/44.8
y = 42.16 л
3. CnH2n+1COOH
W(C) = ((n+1)*Ar(C))/M(CnH2n+1COOH)
0.4 = (12n+12)/(12n+2n+1+12+32+1)
0.4 = (12n+12)/(14n+46)
5.6n+18.4 = 12n+12
-6.4n = -6.4
n = 6.4/6.4 = 1 ==> CH3COOH - уксусная кислота.