1) СаCO3 + 2HCl = CaCl2 + CO2<span> ↑ +H2O
Извини, только 1 знаю...</span>
По пропорции:
m/M= V/Vm
V=(m*Vm)/M
V= 1.2
Дано
AlxOy
w(Al) = 53.8% = 0.538
w(O) = 46.2% = 0.462
Решение
w(Al) = xAr(Al) / (xAr(Al) + yAr(O)) = 27x / (27x + 16y) = 0.538
27x / (27x + 16y) = 0.538
27x = 0.538(27x + 16y)
27x = 14.526x + 8.608y
12.474x = 8.608y
1.5x = 1y
3x = 2y
x : y = 2 : 3
Al2O3
Ответ: Al2O3
а)S+H2=H2S;2H2S+3O2=2H2O=2SO2; SO2+Na2O=Na2SO3 ; Na2SO3+H2O=NaOH+NaHSO3
2NaHSO3 -Na2SO3+SO2+H2O
Б)S+2K - K2S
K2S+Pb(NO3)2=2KNO3+PbS
А-2P2+3O2=2P2O3
b-2Nа+CL2=2NаCL
c-P+5CL=PCL5
d-2АL+3CL2=2АLCL3
e-2HgO=2Hg+O2
f-CH4+2O2=CO2+2H2O