(9x²-25)√(x-1)=0
ОДЗ: х≥1
х-1=0
х1=1
9х²-25=0
9х²=25
х²=25/9
х2=√(25/9)=5/3
х3=-√(25/9)=-5/3
Ответ: х1=1 х2=5/3 х3=-5/3
2,7х-3-х-0,6+0,2=0
1,7х-3,4=0
1,7х=3,4
х=3,4/1,7
х=2
1)5x^2+20x+20=-<span>6x+44,</span>
<span>5x^2+14x-24=0</span>
<span>D=196+4*24*5=676=26^2</span>
<span>x1=1.2 x2=-3</span>
<span>2)2x^2+7x-4=3x^2+11x</span>
<span>-x^2-4x-4=0</span>
<span>x^2+4x+4=0</span>
D=16-16=0
x=-4/2=-2