<span>разложите многочлен на множители
27а^2-18ab = 9a (3a - 2b)</span>
Решение
Sin(3x/2 + π/12) < √2/2
- π - arcsin(√2/2) + 2πk < 3x/2 + π/12 < arcsin(√2/2) + 2πk, k ∈ Z
- π - π/4 + 2πk < 3x/2 + π/12 < π/4<span> + 2πk, k ∈ Z
</span>- 5π/4 + 2πk < 3x/2 < π/4<span> + 2πk, k ∈ Z
</span>- 5π/4 - π/12 + 2πk < 3x/2 < π/4 - π/12 + 2πk, k ∈ Z
- 4π/3 + 2πk < 3x/2 < π/6 <span>+ 2πk, k ∈ Z
</span>- 8π/3 + 4πk < 3x < π/3 <span>+ 4πk, k ∈ Z
</span>- 8π/9 + 4πk/3 < <span>x < </span>π/9 <span>+ 4πk/3, k ∈ Z</span>
Y=3sin(1/2×x+π/3)+1
y=3sin((3x+2π)/6)+1
6⁻⁴*6⁻⁹ 6⁻¹³
------------ = ------------- =6⁻¹ = 1/6
6⁻¹² 6⁻¹²
7⁻⁷*7⁻⁴ 7⁻¹¹ 1
------------- = ----------- = ----------- = 7² = 49
7⁻¹³ 7⁻¹³ 7⁻²
<span> Мне кажется, ответов два: [0;0,3] [ 0 ; 0.3]
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